Differentiation formulas

The Differentiation formula list has been provided by me to help all those students who can not take any coaching or tuition, and it also help all readers those want to learn mathematics (Calculus).

This is my first blog that contain differentiation formulas of a constant, trigonometric functions, algebraic  functions, exponential functions, inverse trigonometric functions and logarithmic functions and many more. 

Before reading the formula we have to know "what is differentiation?"

In many colleges and schools students are asked that what is differentiation? Most of the students can not explain so this BLOG is going to be very important for knowing about differentiation.

So let's talk about differentiation:-

Differentiation means rate of change of a function f(x) with respect to its input x . 

and the rate of change is known as derivative of a function with respect to the x.

It can be represented as d/dx.

Now its time to learn formulas of differentiation:- 

$\frac{d}{dx}$ $f(x)$ = $f^{'}{x}$ $\\$ $\\$ $\frac{d}{dx}$ $c = 0$ where $c$ is a constant value. $\\$ $\\$ $\frac{d}{dx}$$(x)$ = $1$ $\\$ $\\$ $\frac{d}{dx}$$x^{n}$ = $n(x)^{n-1}$,$ $ where n is real number.$\\$ $\\$ $\frac{d}{dx} \sin x = \cos x $ $\\$ $\\$ $\frac{d}{dx}$$\cos x$ = $-\sin x$$\\$ $\\$ $\frac{d}{dx}$$\tan x$ = $\sec^{2} x$$\\$ $\\$ $\frac{d}{dx}$$\cot x$ = $-\csc^{2} x$$\\$ $\\$ $\frac{d}{dx}$$\sec x$ = $\sec x \tan x $$\\$ $\\$ $\frac{d}{dx}$$\csc x $ = $-\csc x \cot x $$\\$ $\\$ $\frac{d}{dx}$$\sin^{-1} x$ = $\frac{1}{\sqrt{1-x^{2}}}$$\\$ $\\$ $\frac{d}{dx}$$\cos^{-1} x$ = $-\frac{1}{\sqrt{1-x^{2}}}$$\\$ $\\$ $\frac{d}{dx}$$\tan^{-1} x$ = $\frac{1}{1+x^{2}}$ $\\$ $\\$ $\frac{d}{dx}$$\cot^{-1}x$ = $-\frac{1}{1+x^{2}}$ $\\$ $\\$ $\frac{d}{dx}$$\sec^{-1}x$ = $\frac{1}{|x|\sqrt{1-x^{2}}}$ $\\$ $\\$ $\frac{d}{dx}$$\csc^{-1}x$ = $-\frac{1}{|x|\sqrt{1-x^{2}}}$ $\\$ $\\$ $\frac{d}{dx}$ $e^{x}$ = $e^{x}$ $\\$ $\\$ $\frac{d}{dx}$$a^{x}$ = $a^{x}\ln a $ $\\$ $\\$ $\frac{d}{dx}$$\ln x $ = $\frac{1}{|x|}$ $\\$ $\\$ Derivative of $x$ from the first principle of differentiation. $\\$ $\\$ $\frac{d}{dx}$$f(x)$ = $f^{'}(x)$ = $\lim_{x\to 0}\frac{f(x+h) - f(x)}{h} $ $\\$ $\\$ If there are two functions $u$ and $v$,$\\$ then $\frac{d}{dx}$$(uv)$ = $u\frac{d}{dx}v + v\frac{d}{dx}u$ $\\$ Namaste to my all readers Please Guys share this blog post if this blog post helped you to learn differentiation. wait for my next blog post. My blogs help you to learn calculus from basic to high level. $\\$ THANKS! $\\$ support.